Your grade so far, based on the first 2 midterms, is
((61 * 25) + (39 * 35))/(25 + 35) = (1525 + 1365)/60 = 2890/60 = (approximately) 48%
It's not just (61 + 39)/2 because the two tests have different weights.
If we let x be your grade on midterm 3 and y be your grade on whatever that remaining 5% comes from, then your final grade will be
(61 * 0.25) + (39 * 0.35) + (x * 0.35) + (y * 0.05)
(Do you see where I got each of those numbers? That's how you calculate a final grade based on grades in various categories with various weights.)
Since 61 * 0.25 = 15.25 and 39 * 0.35 = 13.65, and since 15.25 + 13.65 = 28.9,
(61 * 0.25) + (39 * 0.35) + (x * 0.35) + (y * 0.05) = 28.9 + 0.35x + 0.05y
Let's assume that you get a perfect score on both your 3rd midterm and on whatever that last 5% of your grade is. That's the best you can possibly do, so the best grade you can possibly still earn is
28.9 + (100 * 0.35) + (100 * 0.05)
which, of course, is equal to
28.9 + 35 + 5
which is
68.9
That's the best you can do mathematically. However, it is relatively unlikely that a student who has a grade of 48% before the 3rd midterm will score 100% on that 3rd midterm, so the best you can do based on my knowledge of human beings is a bit less than 68.9%.
Good luck on the test.